50b^2+20b+2=0

Solution for 50b^2+20b+2=0 equation:

Simplifying
50b2 + 20b + 2 = 0

Reorder the terms:
2 + 20b + 50b2 = 0

Solving
2 + 20b + 50b2 = 0

Solving for variable 'b'.

Factor out the Greatest Common Factor (GCF), '2'.
2(1 + 10b + 25b2) = 0

Factor a trinomial.
2((1 + 5b)(1 + 5b)) = 0

Ignore the factor 2.
Subproblem 1
Set the factor '(1 + 5b)' equal to zero and attempt to solve:

Simplifying
1 + 5b = 0

Solving
1 + 5b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + 5b = 0 + -1

Combine like terms: 1 + -1 = 0
0 + 5b = 0 + -1
5b = 0 + -1

Combine like terms: 0 + -1 = -1
5b = -1

Divide each side by '5'.
b = -0.2

Simplifying
b = -0.2
Subproblem 2
Set the factor '(1 + 5b)' equal to zero and attempt to solve:

Simplifying
1 + 5b = 0

Solving
1 + 5b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + 5b = 0 + -1

Combine like terms: 1 + -1 = 0
0 + 5b = 0 + -1
5b = 0 + -1

Combine like terms: 0 + -1 = -1
5b = -1

Divide each side by '5'.
b = -0.2

Simplifying
b = -0.2
Solution
b = {-0.2, -0.2}